l 2x + 6 l - 4 = -20 add 4 to both sides
l 2x + 6 l = -16
Note that this has no solution because absolute value is always positive (or 0).......thus, the left side [ a positive, or zero] cannot equal the right side [ a negative]
l 2x + 6 l - 4 = -20
l 2x + 6 l + 16 = 0
2x + 22 = 0
x + 11 = 0
x = -11
Am i wrong?
Sorry, Max.....I believe you made an error....look at your second step....you have.....
l 2x + 6 l + 16 = 0 (1)
If we claim that the answer is -11, then we have
l 2(-11) + 6 l + 16 = 0
l -22 + 6 l + 16 = 0
l -16 l + 16 = 0
16 + 16 = 0
32 = 0 .......which is clearly false
We have no solution because the left side of (1) will always be > 0