what is the answer to this. when the original price of a car is 25,000 and it depreciates by 8% each year, what is the price after the 6th year?
After 1 year the price is (1-0.08)*25000 = 0.92*25000.
After 2 years the price is (1-0.08)*0.92*25000 = 0.922*25000
After 3 years the price is (1-0.08)*0.922*25000 = 0.923*25000
etc. until
After 6 years the price is (1-0.08)*0.925*25000 = 0.926*25000
$${{\mathtt{0.92}}}^{{\mathtt{6}}}{\mathtt{\,\times\,}}{\mathtt{25\,000}} = {\mathtt{15\,158.875\: \!033\: \!6}}$$
After 1 year the price is (1-0.08)*25000 = 0.92*25000.
After 2 years the price is (1-0.08)*0.92*25000 = 0.922*25000
After 3 years the price is (1-0.08)*0.922*25000 = 0.923*25000
etc. until
After 6 years the price is (1-0.08)*0.925*25000 = 0.926*25000
$${{\mathtt{0.92}}}^{{\mathtt{6}}}{\mathtt{\,\times\,}}{\mathtt{25\,000}} = {\mathtt{15\,158.875\: \!033\: \!6}}$$