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what is the answer to this. when the original price of a car is 25,000 and it depreciates by 8% each year, what is the price after the 6th year?

 Apr 29, 2014

Best Answer 

 #1
avatar+33666 
+5

After 1 year the price is (1-0.08)*25000 = 0.92*25000.

After 2 years the price is (1-0.08)*0.92*25000 = 0.922*25000

After 3 years the price is (1-0.08)*0.922*25000 = 0.923*25000

etc. until

After 6 years the price is (1-0.08)*0.925*25000 = 0.926*25000

$${{\mathtt{0.92}}}^{{\mathtt{6}}}{\mathtt{\,\times\,}}{\mathtt{25\,000}} = {\mathtt{15\,158.875\: \!033\: \!6}}$$

 Apr 29, 2014
 #1
avatar+33666 
+5
Best Answer

After 1 year the price is (1-0.08)*25000 = 0.92*25000.

After 2 years the price is (1-0.08)*0.92*25000 = 0.922*25000

After 3 years the price is (1-0.08)*0.922*25000 = 0.923*25000

etc. until

After 6 years the price is (1-0.08)*0.925*25000 = 0.926*25000

$${{\mathtt{0.92}}}^{{\mathtt{6}}}{\mathtt{\,\times\,}}{\mathtt{25\,000}} = {\mathtt{15\,158.875\: \!033\: \!6}}$$

Alan Apr 29, 2014

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