Solve the equation below
6. Multiply: (x – 4)(x + 5)
(a) x2 + 5x - 20, (b) x2 - 4x - 20, (c) x2 - x - 20, (d) x2 + x - 20.
\((x – 4)(x + 5) \implies x^2 - 4x + 5x -20 \implies \boxed {x^2 +x - 20}\)
(x-4)(x+5)=x^2+x-20=(d) is our final solution.