+14985 (216x^9)^2/3
\(\left(216x^{9} \right) ^{\frac{2}{3} } \) = \(\) \(\sqrt[3]{46656x^{18} } \) = \({\color{blue}36x^6}\)
\(\frac{\left(216\times x^{9}\right)^2 }{3} \) = \(\frac{46656x^{18} }{3} = {\color{blue}15552x^{18} }\)
asinus :- ) 
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+33653 Your second step is irrelevant asinus!
\((216x^9)^{2/3} \rightarrow(216^{1/3}x^{9\times1/3})^2 \rightarrow (6x^3)^2 \rightarrow 6^2x^{3\times2}\rightarrow 36x^6\)
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+33653 Oh, ok asinus, I see you have assumed the original might have been such that the 3 is not part of the exponent, which is strictly correct according to the normal hierarchy rules. However, it's extremely unlikely that that is what is meant in this sort of question I could be wrong of course!).
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