We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

What is the area, in square units, of the interior region formed by the lines $y = 4x - 6, y = -2x +12$ and the $y$-axis?

Guest Jun 24, 2018

#2**+2 **

This region will form a triangle

To find the height of this triangle, let us fihd the x value of the intersection of the lines....set the y's equal

4x - 6 = -2x + 12 add 2x to both sides, add 6 to both sides

6x = 18 divide both sides by 6

x = 3 this x value will be the height of the triangle

And the y intercept of 4x - 6 = -6

And the y intercept of -2x + 12 = 12

So....the length of the base of this triangle = 12 - (-6) = 18

So....the area of the tiriangle is (1/2) (base length) (height) = (1/2)(18)(3) = 27 units^2

Here's a pic :

https://www.desmos.com/calculator/9svh83h2ij

CPhill Jun 25, 2018