What is the area, in square units, of the square with the four vertices at $A\ (0, 0)$, $B\ (-5, -1)$, $C\ (-4, -6)$ and $D\ (1, -5)$?

Using the Pythagorean Theorem, the side length of the sqaure is \(\sqrt{26} \), meaning that the square's area is: \(\sqrt{26}^2 = \color{brown}\boxed{26}\)