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# What is the area, in square units, of the square with the four vertices at $A\ (0, 0)$, $B\ (-5, -1)$, $C\ (-4, -6)$ and $D\ (1, -5)$?

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What is the area, in square units, of the square with the four vertices at $A\ (0, 0)$, $B\ (-5, -1)$, $C\ (-4, -6)$ and $D\ (1, -5)$?

Feb 28, 2022

Using the Pythagorean Theorem, the side length of the sqaure is $$\sqrt{26}$$, meaning that the square's area is: $$\sqrt{26}^2 = \color{brown}\boxed{26}$$