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What is the area of the composite figure whose vertices have the following coordinates?

(−2, −2)(−2, −2) , (4, −2)(4, −2) , (5, 1)(5, 1) , (2, 3)(2, 3) , (−1, 1)

Enter your answer in the box.

___ units²

Sorry for the easy question, I'm just dumb

Guest Feb 18, 2019

#1**-2 **

Area of a rectangle = W X L Area of a rectangle = 5 X 2 Area of a rectangle = 10 Area of triangle 1= 1/2 X B X H Area of triangle 1= 1/2 X 2 X 2 Area of triangle 1= 1/2 X 4

This is someting that might help you!

Pigglepoox2007 Feb 18, 2019

#5**0 **

Sorry so so sorry got carried away well if it helps let it rip then!!!!!!!!!

Pigglepoox2007
Feb 18, 2019

#6**-2 **

I the answer I believe is 30 squared units. and your not dumb you won't get far discouraging yourself think more positive and you will be real good at whatever you aim for.

HiylinLink Feb 18, 2019

#9**+4 **

**What is the area of the composite figure whose vertices have the following coordinates?**

**(−2, −2) , (4, −2) , (5, 1) , (2, 3) , (−1, 1)**

\(\begin{array}{|r|r|r|r|r|} \hline \text{Point} & x & y & \\ \hline 1 & -2 & -2 &\\ & & & (-2)(-2) - 4(-2) & = 12 \\ 2 & 4 & -2 & \\ & & & 4\cdot 1 - 5 (-2) & = 14 \\ 3 & 5 & 1 &\\ & & & 5\cdot 3 - 2 (1) & = 13 \\ 4 & 2 & 3 &\\ & & & 2\cdot 1 - (-1)3 & = 5 \\ 5 & -1 & 1 &\\ & & & (-1)(-2) - (-2)1 & = 4 \\ 1 & -2 & -2 & \\ \hline & & & & \text{sum} = 48 \\ & & & & \text{area of the composite figure } = \dfrac{\text{sum}}{2} = \dfrac{\text{48}}{2} = \mathbf{24} \\ \hline \end{array}\)

heureka Feb 19, 2019