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What is the area of the rectangle shown on the coordinate plane?

 

Enter your answer in the box. Do not round at any steps.

 

AngelRay  Nov 13, 2017
 #1
avatar+86859 
+1

One dimension   =  sqrt [ ( -4 - - 1)^2 + ( 1 - -2)^2 ]  = sqrt [ (-3)^2 + (3)^2 ] =

 

sqrt [ 9 + 9 ]  =  sqrt [ 18]   =   sqrt [ 9 * 2  ] =  3sqrt[2]

 

The other dimension  = sqrt [ ( -4 -  -6)^2 + ( 1 -  - 1)^2 ]  =  sqrt [ (2)^2 + (2)^2 ] =

 

sqrt [ 4 + 4] =  sqrt [8]  =  sqrt [ 4 * 2 ]  =  2sqrt[2]

 

 

So....the area  is     [  3sqrt (2)  * 2 sqrt (2) ]  =  6 * 2   = 12 units^2

 

 

 

cool cool cool

CPhill  Nov 13, 2017

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