+912 What is the area of the rectangle shown on the coordinate plane?
Enter your answer in the box. Do not round at any steps.
+130081 One dimension = sqrt [ ( -4 - - 1)^2 + ( 1 - -2)^2 ] = sqrt [ (-3)^2 + (3)^2 ] =
sqrt [ 9 + 9 ] = sqrt [ 18] = sqrt [ 9 * 2 ] = 3sqrt[2]
The other dimension = sqrt [ ( -4 - -6)^2 + ( 1 - - 1)^2 ] = sqrt [ (2)^2 + (2)^2 ] =
sqrt [ 4 + 4] = sqrt [8] = sqrt [ 4 * 2 ] = 2sqrt[2]
So....the area is [ 3sqrt (2) * 2 sqrt (2) ] = 6 * 2 = 12 units^2
