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What is the area of the rectangle shown on the coordinate plane?

 

Enter your answer in the box. Do not round at any steps.

  unitsĀ²

queend1998  Dec 21, 2017
edited by Guest  Dec 21, 2017
 #1
avatar+88899 
+2

Let A  =  length of one side

 

A  =  sqrt   [ (1 - 4)^2  + (5 - 3)^2 ]  =  sqrt [ (-3)^2  + 2^2 ]  = sqrt [13]

 

Let  B  =  length of perpendicular side

 

B  = sqrt [ (4 - 0)^2  +  ( 3 -  -3)^2 ]  =  sqrt [ 4^2  + 6^2]  =  sqrt [ 52]  = sqrt [ 4 * 13]  =

2*sqrt [13]

 

So.....the area  =  A * B  =  sqrt [13] * 2 sqrt [13]  = 2 * 13  =  26 units^2 

 

 

cool cool cool

CPhill  Dec 21, 2017

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