What is the area of the regular 30-gon with radius 15 mm?
This will form 30 congruent triangles
Each triangle will have an included angle of 360 / 30 = 12°
And the sides surrounding this angle = 15
So the area of these 30 triangles =
30 (1/2) (15)^2 * sin (12°) =
15^3 * sin (12°) ≈ 701.7 mm^2
