What is the area of this triangle. Only round your final answer to the nearest hundredth.

You need the bases and heights of the triangles to find the areas.

All of these are exactly the same....

Area =  (1/2)(product of two given sides) (sine of the included angle)

Area of 1st one  =   (1/2)(7.5)(13)sin(94)   ≈ 48.63 in^2

You should be able to do the rest......pay attention to the units given......!!!!!

Four tasks

\(\large A=\frac{1}{2}\ ab\ sin\gamma\)

(a)

What is the area of this triangle. Only round your final answer to the nearest hundredth.

\(\large A=\frac{1}{2}\cdot 13\cdot7.5\ inch^2\ sin \ 94°=48.63\ inch^2\)

(b)

What is the area of this panel? Round your final answer to the nearest tenth.

\(\large A=\frac{1}{2}\cdot 12\cdot14\ ft^2\ sin \ 20°=28.7\ ft^2\)

(c)

A triangular pennet has two sides that are 90 cm long each with an included angle of 25dg. What is the area of this pennant? Round only your final answer to the nearest tenth.

\(\large A=\frac{1}{2}\cdot 90\cdot90\ cm^2\ sin \ 25°=1711.6cm^2\)

(d)

What is the area of Triangle RST? Round only your final answer to the nearest tenth. 

\(\large A=\frac{1}{2}\cdot 8\cdot9\ yd^2\ sin \ 47°=26.3\ yd^2\)

  !