What is the axis of symmetry, y intercept, vertex and whether the parabola opens up or down of these equations?
1) y=2x^2-8x+8
2) y=-x^2+2x+1
3) y= 1/2x^2+2x-8
and
4) y= -3x^2 + 6x
Thank you so much
The graphs of all are parabolas. Parabolas have the format: ax2 + bx + c = 0
Whether the parabola is facing up or down can be determined by the sign before the "a". Up is +, down is -
The y-intercept occurs where the value of x in the equation is zero.
You can find the x-value of the vertex by (-b/2a), then use this to find the y-value.
Note that the vertex and the axis of sym have the same x -value.
The graphs of all are parabolas. Parabolas have the format: ax2 + bx + c = 0
Whether the parabola is facing up or down can be determined by the sign before the "a". Up is +, down is -
The y-intercept occurs where the value of x in the equation is zero.
You can find the x-value of the vertex by (-b/2a), then use this to find the y-value.
Note that the vertex and the axis of sym have the same x -value.
