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what is the center and radius of the circle represented by the following equation: (x+3)^2 + (y-6)^2=81?

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what is the center and radius of the circle represented by the following equation: (x+3)^2 + (y-6)^2=81?

Guest May 24, 2017
#1
+7324
+1

When the equation of a circle is in this format:

(x - h)2 + (y - k)2 = r2     ,

The center of the circle is (h, k) and the radius is r.

So...if the equation of a circle is:

(x + 3)2 + (y - 6)2 = 81

h = -3

k = 6

r2 = 81

r   = $$\sqrt{81}$$

r   = 9

The center of the circle is (-3, 6) and the radius is 9.

hectictar  May 24, 2017