+0  
 
0
283
1
avatar

what is the center and radius of the circle represented by the following equation: (x+3)^2 + (y-6)^2=81?

Guest May 24, 2017
 #1
avatar+7155 
+1

When the equation of a circle is in this format:

(x - h)2 + (y - k)2 = r2     ,

The center of the circle is (h, k) and the radius is r.

 

 

So...if the equation of a circle is:

 

(x + 3)2 + (y - 6)2 = 81

 

h = -3

 

k = 6

 

r2 = 81

r   = \(\sqrt{81}\)

r   = 9

 

The center of the circle is (-3, 6) and the radius is 9.

hectictar  May 24, 2017

9 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.