what is the cube root of x to the power of 57

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Guest Nov 8, 2014

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Best Answer

The cube root of x can be written as x^(1/3)

So, this raised to the 57th power is .... [ x^(1/3)]^57 and by a property of exponents (a^m)ⁿ = a^m*n

So we have [ x^(1/3)]^57 = x^(1/3)*57= x¹⁹

CPhill Nov 8, 2014

CPhill · Answer 1 · 2014-11-08T08:36:17

The cube root of x can be written as x^(1/3)

So, this raised to the 57th power is .... [ x^(1/3)]^57 and by a property of exponents (a^m)ⁿ = a^m*n

So we have [ x^(1/3)]^57 = x^(1/3)*57= x¹⁹