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what is the derivative of g(t)=t(4-t)^1/2

 Oct 9, 2014

Best Answer 

 #1
avatar+130511 
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g(t)=t(4-t)^1/2        we can use the product and chain rules here

g'(t)  = (4-t)^1/2  + (1/2)t(4-t)^(-1/2)(-1) = (4-t)^1/2 - (1/2)t(4-t)^(-1/2) =

.......(factoring).....   (4-t)^(-1/2) [ (4-t) - (1/2)t]   =  (4-t)^(-1/2)[4- (3/2)t ] =

(4-t)^(-1/2) [(8 -3t)/2]

 

 Oct 9, 2014
 #1
avatar+130511 
+5
Best Answer

g(t)=t(4-t)^1/2        we can use the product and chain rules here

g'(t)  = (4-t)^1/2  + (1/2)t(4-t)^(-1/2)(-1) = (4-t)^1/2 - (1/2)t(4-t)^(-1/2) =

.......(factoring).....   (4-t)^(-1/2) [ (4-t) - (1/2)t]   =  (4-t)^(-1/2)[4- (3/2)t ] =

(4-t)^(-1/2) [(8 -3t)/2]

 

CPhill Oct 9, 2014

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