f(x)=(x+3)/sqrt{x-8}
What is the domain?
\(\begin{array}{|rcll|} \hline x-8 &>& 0 \quad &| \quad +8\\ \mathbf{x} &\mathbf{>}& \mathbf{8}\\ \hline \end{array}\)
\(\begin{array}{|rcll|} \hline \sqrt{x-8} & \ne & 0 \\ x-8 & \ne & 0^2 \quad &| \quad +8\\ \mathbf{x} & \mathbf{\ne} & \mathbf{8}\\ \hline \end{array}\)
The domain is x > 8