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f(x)=(x+3)/sqrt{x-8}

 Oct 20, 2016
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f(x)=(x+3)/sqrt{x-8}

What is the domain?

 

\(\begin{array}{|rcll|} \hline x-8 &>& 0 \quad &| \quad +8\\ \mathbf{x} &\mathbf{>}& \mathbf{8}\\ \hline \end{array}\)

 

\(\begin{array}{|rcll|} \hline \sqrt{x-8} & \ne & 0 \\ x-8 & \ne & 0^2 \quad &| \quad +8\\ \mathbf{x} & \mathbf{\ne} & \mathbf{8}\\ \hline \end{array}\)

 

The domain is x > 8

 

 

laugh

 Oct 21, 2016

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