What is the equation of a circle whose center is (-1, 2) and it's radius is 3?

Hi Severoth!

 

To standard equation for a circle with its radius \( r\), and center \((h,k)\) is:

 

\((x - h)^2 + (y - k)^2 = r^2\)

 

Since your circle has a center \((-1,2)\) and a radius \(3\), 

 

The equation will be:

 

\((x+1)^2+(y-2)^2=9\)

 

I hope this helps, 

 

Gavin.