+0  
 
-1
113
1
avatar+102 

What is the equation of a circle whose center is (-1, 2) and it's radius is 3? 

Severoth  Apr 27, 2018

Best Answer 

 #1
avatar+942 
+4

Hi Severoth!

 

To standard equation for a circle with its radius \( r\), and center \((h,k)\) is:

 

\((x - h)^2 + (y - k)^2 = r^2\)

 

Since your circle has a center \((-1,2)\) and a radius \(3\)

 

The equation will be:

 

\((x+1)^2+(y-2)^2=9\)

 

I hope this helps, 

 

Gavin.

GYanggg  Apr 27, 2018
 #1
avatar+942 
+4
Best Answer

Hi Severoth!

 

To standard equation for a circle with its radius \( r\), and center \((h,k)\) is:

 

\((x - h)^2 + (y - k)^2 = r^2\)

 

Since your circle has a center \((-1,2)\) and a radius \(3\)

 

The equation will be:

 

\((x+1)^2+(y-2)^2=9\)

 

I hope this helps, 

 

Gavin.

GYanggg  Apr 27, 2018

19 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.