+122 What is the equation of a circle whose center is (-1, 2) and it's radius is 3?
+983 Hi Severoth!
To standard equation for a circle with its radius \( r\), and center \((h,k)\) is:
\((x - h)^2 + (y - k)^2 = r^2\)
Since your circle has a center \((-1,2)\) and a radius \(3\),
The equation will be:
\((x+1)^2+(y-2)^2=9\)
I hope this helps,
Gavin.
