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What is the equation of a circle whose center is (-1, 2) and it's radius is 3? 

Severoth  Apr 27, 2018

Best Answer 

 #1
avatar+626 
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Hi Severoth!

 

To standard equation for a circle with its radius \( r\), and center \((h,k)\) is:

 

\((x - h)^2 + (y - k)^2 = r^2\)

 

Since your circle has a center \((-1,2)\) and a radius \(3\)

 

The equation will be:

 

\((x+1)^2+(y-2)^2=9\)

 

I hope this helps, 

 

Gavin.

GYanggg  Apr 27, 2018
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1+0 Answers

 #1
avatar+626 
+4
Best Answer

Hi Severoth!

 

To standard equation for a circle with its radius \( r\), and center \((h,k)\) is:

 

\((x - h)^2 + (y - k)^2 = r^2\)

 

Since your circle has a center \((-1,2)\) and a radius \(3\)

 

The equation will be:

 

\((x+1)^2+(y-2)^2=9\)

 

I hope this helps, 

 

Gavin.

GYanggg  Apr 27, 2018

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