What is the equation of a circle whose center is (-1, 2) and it's radius is 3?

Hi Severoth!

To standard equation for a circle with its radius $r$, and center $(h,k)$ is:

$(x - h)^2 + (y - k)^2 = r^2$

Since your circle has a center $(-1,2)$ and a radius $3$, 

The equation will be:

$(x+1)^2+(y-2)^2=9$

I hope this helps, 

Gavin.