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What is the equation of a line that contains point (–2, 5) and is PERPENDICULAR to y = (1/2)x + 6?

 Oct 1, 2020
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What is the equation of a line that contains point (–2, 5) and is PERPENDICULAR to y = (1/2)x + 6?

 

Hello Guest!

 

\(m=-\large \frac{1}{\frac{1}{2}}\)

\(m=-2\)

\(y=m(x+x_1)+y_1\)

\(y=-2(x+2)+5\)

\(y=-2x+1\)

laugh  !

 Oct 1, 2020
edited by asinus  Oct 1, 2020

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