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# What is the equation of a line that contains point (–2, 5) and is PERPENDICULAR to y = (1/2)x + 6?

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What is the equation of a line that contains point (–2, 5) and is PERPENDICULAR to y = (1/2)x + 6?

Oct 1, 2020

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What is the equation of a line that contains point (–2, 5) and is PERPENDICULAR to y = (1/2)x + 6?

Hello Guest!

$$m=-\large \frac{1}{\frac{1}{2}}$$

$$m=-2$$

$$y=m(x+x_1)+y_1$$

$$y=-2(x+2)+5$$

$$y=-2x+1$$

!

Oct 1, 2020
edited by asinus  Oct 1, 2020