+0  
 
0
28
1
avatar

What is the equation of the line that crosses the y-intercept at 12 and perpendicular to 7x + 6y = 17?

 Feb 25, 2019
 #1
avatar+98091 
+1

Let's find the slope to   7x + 6y = 17

The slope in the form Ax + By = C  is    -A / B

So....the slope is  -7 / 6

 

And a perpendicular line to this will have negative reciprocal slope =    6/7  = m

 

And  if this perpendicular line has a y intercept of 12....the point (0, 12) is on the line = (x1, y1)

 

So...the equation is

 

y = m ( x - x1) + y1         fill in what we know

 

y = (6/7) ( x - 0 ) + 12

 

y = (6/7)x + 12

 

Here's a graph : https://www.desmos.com/calculator/oyd29rauvm

 

cool cool cool

 Feb 25, 2019

14 Online Users