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What is the equation of the line that crosses the y-intercept at 12 and perpendicular to 7x + 6y = 17?

Guest Feb 25, 2019

#1**+1 **

Let's find the slope to 7x + 6y = 17

The slope in the form Ax + By = C is -A / B

So....the slope is -7 / 6

And a perpendicular line to this will have negative reciprocal slope = 6/7 = m

And if this perpendicular line has a y intercept of 12....the point (0, 12) is on the line = (x1, y1)

So...the equation is

y = m ( x - x1) + y1 fill in what we know

y = (6/7) ( x - 0 ) + 12

y = (6/7)x + 12

Here's a graph : https://www.desmos.com/calculator/oyd29rauvm

CPhill Feb 25, 2019