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What is the equation of the line that passes through the point (-2,10) and is parallel to the line y = -4x - 3?

 Nov 2, 2015

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 #1
avatar+26400 
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What is the equation of the line that passes through the point (-2,10) and is parallel to the line y = -4x - 3?

 

\(\begin{array}{rcl} \boxed{~ \begin{array}{rcl} y &=& m\cdot x +b \\ \end{array} ~}\\ (1) & x_1 &=& -2 \\ & y_1 &=&10\\ \hline & y_1 &= &m \cdot x_1 + b\\ & 10 &= &m \cdot (-2) + b\\ \hline (2) & y &=& -4x-3\\ & \text{slope } m &=& -4 \qquad \text{parallel line}\\ &\mathbf{m} &\mathbf{=}& \mathbf{4}\\ \hline & 10 &= &(-4) \cdot (-2) + b\\ & 10 &= &8 + b\\ &2 &= & b\\ &\mathbf{b} &\mathbf{=}& \mathbf{2}\\ \hline \boxed{~ \begin{array}{rcl} y &=& m\cdot x +b \\ y &=& -4x + 2 \end{array} ~} \end{array}\)

 

laugh

 Nov 2, 2015
 #1
avatar+26400 
+30
Best Answer

What is the equation of the line that passes through the point (-2,10) and is parallel to the line y = -4x - 3?

 

\(\begin{array}{rcl} \boxed{~ \begin{array}{rcl} y &=& m\cdot x +b \\ \end{array} ~}\\ (1) & x_1 &=& -2 \\ & y_1 &=&10\\ \hline & y_1 &= &m \cdot x_1 + b\\ & 10 &= &m \cdot (-2) + b\\ \hline (2) & y &=& -4x-3\\ & \text{slope } m &=& -4 \qquad \text{parallel line}\\ &\mathbf{m} &\mathbf{=}& \mathbf{4}\\ \hline & 10 &= &(-4) \cdot (-2) + b\\ & 10 &= &8 + b\\ &2 &= & b\\ &\mathbf{b} &\mathbf{=}& \mathbf{2}\\ \hline \boxed{~ \begin{array}{rcl} y &=& m\cdot x +b \\ y &=& -4x + 2 \end{array} ~} \end{array}\)

 

laugh

heureka Nov 2, 2015

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