what is the equation of the line that passes through the points (-4 , 2) and (6 , 6) ?
+130511 Let's find the slope, first = change in y / change in x
Note that from (-4,2) to (6,6),
y changes by 4, and x changes by 10, so the slope is 4/10 = 2/5
So using one of the points - I'll use (6,6) - we have, writing in "point-slope" form:
y - 6 = (2/5)(x-6)
y - 6 = (2/5)x - 12/5 Add 6 to both sides
y = (2/5)x + 18/5 And that's in the form..... y = mx + b
You should verify that both points "check" in this equation........
+130511 Let's find the slope, first = change in y / change in x
Note that from (-4,2) to (6,6),
y changes by 4, and x changes by 10, so the slope is 4/10 = 2/5
So using one of the points - I'll use (6,6) - we have, writing in "point-slope" form:
y - 6 = (2/5)(x-6)
y - 6 = (2/5)x - 12/5 Add 6 to both sides
y = (2/5)x + 18/5 And that's in the form..... y = mx + b
You should verify that both points "check" in this equation........
