What is the equation of this circle in general form?
x2+y2−2x−6y−26=0
x2+y2+2x+6y−26=0
x² + y² + 2x + 6y + 4 = 0
x2+y2−2x−6y+4=0
The center is (1,3) and the radius is 6 ..... so we have....
(x - 1)^2 + ( y - 3)^2 = 36 expand
x^2 - 2x + 1 + y^2 - 6y + 9 = 36 rearrange
x^2 + y^2 -2x - 6y + 10 = 36 subtract 36 from both sides
x^2 + y^2 - 2x - 6y - 26 = 0
+595 
