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# what is the equation

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(2,16)(5,30)

Feb 12, 2019

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1. Note the equation $$\frac{Y_2-Y_1}{X_2-X_1}$$

2. Substitute $$\frac{(30)-(16)}{(5)-(2)}$$

3. Solve $$\frac{14}{3}$$

4.  Note the equation $$y=mx+b$$

We already have $$m$$, which is $$\frac{14}{3}$$

So $$y=\frac{14}{3}x+b$$

5. Substitute a coordinate $$(x,y)$$, from the problem

Take $$(2,16)$$ and substitute it in to get: $$16=\frac{14}{3}*(2)+b$$

Solving we get $$b=\frac{20}{3}$$

6. Put $$b$$ and $$m$$ together to make the equation $$\boxed{y=\frac{14}{3}x+\frac{20}{3}}$$

Feb 12, 2019

#1
+3

1. Note the equation $$\frac{Y_2-Y_1}{X_2-X_1}$$

2. Substitute $$\frac{(30)-(16)}{(5)-(2)}$$

3. Solve $$\frac{14}{3}$$

4.  Note the equation $$y=mx+b$$

We already have $$m$$, which is $$\frac{14}{3}$$

So $$y=\frac{14}{3}x+b$$

5. Substitute a coordinate $$(x,y)$$, from the problem

Take $$(2,16)$$ and substitute it in to get: $$16=\frac{14}{3}*(2)+b$$

Solving we get $$b=\frac{20}{3}$$

6. Put $$b$$ and $$m$$ together to make the equation $$\boxed{y=\frac{14}{3}x+\frac{20}{3}}$$

CalculatorUser Feb 12, 2019
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