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What is the exact value of cosØ when Ø lies in quadrant 1 and sinØ= the square root of 2 over 6?

Guest Jul 21, 2017
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Let cos(Ø) = x/r.

Let sin(Ø) = y/r

Since sin(Ø) = sqrt(2) / 6     --->     y = sqrt(2)     and     r = 6.

By the Pythagorean Identity,  x2 + y2  =  r2     --->     x2 + ( sqrt(2) )2  =  62     --->     x2 + 2  =  34     --->     x  =  sqrrt(34)

Therefore  cos(Ø)  =  sqrt(34) / 6

geno3141  Jul 21, 2017

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