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cosθ=−2/ √3, where π≤θ≤3π/ 2

tanβ=4/ 3, where 0≤β≤π/ 2

 

Enter your answer, as a fraction in simplified form

 Jan 22, 2021
 #1
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cosθ=−2/ √3, where π≤θ≤3π/ 2

tanβ=4/ 3, where 0≤β≤π/ 2

 

Hello lovesosa12!

 

\(cosθ=−2/ √3, where\ π≤θ≤3π/ 2\)

θ cannot be determined because

\(-1\leq cos\ θ\leq 1\)  and  \(-\frac{2}{\sqrt{3}}<1\)

 

tanβ=4/ 3, where 0≤β≤π/ 2

\(\beta=arctan(4/3)\)

\(\beta = 53.13\ deg\)

laugh  !

 Jan 22, 2021

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