cosθ=−2/ √3, where π≤θ≤3π/ 2
tanβ=4/ 3, where 0≤β≤π/ 2
Hello lovesosa12!
\(cosθ=−2/ √3, where\ π≤θ≤3π/ 2\)
θ cannot be determined because
\(-1\leq cos\ θ\leq 1\) and \(-\frac{2}{\sqrt{3}}<1\)
tanβ=4/ 3, where 0≤β≤π/ 2
\(\beta=arctan(4/3)\)
\(\beta = 53.13\ deg\)
!