what is the exponent rule of (2a^-3b)(6b^5c^-7)/4c^-9

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Guest Mar 23, 2017

Guest · Answer 1 · 2017-03-23T09:00:10

I think it is 2... Not sure Though. Lol.. TTYL.. XOX

CPhill · Answer 2 · 2017-03-23T09:27:47

(2a^-3b)(6b^5c^-7) / ( 4c^-9) =

[2 * 6 / 4 ] * [b * b^5] * [ 1 / a^3] * [ c^9 / c^7] =

[12 / 4] * [ b^6 ] * [ 1 / a^3 ] * [ c ^2 ] =

[ 3 b^6 c^2 ] / a^3