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what is the first five terms of the sequence an=2n^2

 May 11, 2015

Best Answer 

 #2
avatar+23254 
+5

Since an  =  2n2

--->   a1  =  2(1)2 =  2(1)  =  2

         a2  =  2(2)2 =  2(4)  =  8

         a3  =  2(3)2 =  2(9)  =  18

Can you do a4 and a5?

 May 11, 2015
 #1
avatar+130462 
+5

2(1)^2 , 2(2)^2 , 2(3)^2, 2(4)^2, 2(5)^2  =

2, 8, 18, 32, 50

 

  

 May 11, 2015
 #2
avatar+23254 
+5
Best Answer

Since an  =  2n2

--->   a1  =  2(1)2 =  2(1)  =  2

         a2  =  2(2)2 =  2(4)  =  8

         a3  =  2(3)2 =  2(9)  =  18

Can you do a4 and a5?

geno3141 May 11, 2015

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