What is the inverse of [2x+1/3]
\(y=2x+1/3\\ y-1/3=2x\\ x=\frac{1}{2}(y-\frac{1}{3})\\ x=\frac{1}{2}(\frac{3y-1}{3})\\ x=\frac{3y-1}{6}\\ \mbox{The inverse is }\\ y=\frac{3x-1}{6}\\\)