What is the inverse of f(x) = The quantity of three x plus five, over seven?

f(x) = [3x + 5]/ 7    first, write f(x) as y...so we have

y = [3x + 5] / 7       we want to get x by itself.....multiply both sides by 7

7y = 3x + 5             subtract 5 from both sides

7y - 5 = 3x              divide both sides by 3

[7y - 5]/ 3  = x        "exchange" x and y  

[7x - 5] /3 = y          for "y,' write f^-1(x)....

[7x - 5] / 3 = f^-1(x)   and that's it !!