#1**+1 **

y = x^(x-1) solve for 'x

log (y) = (x-1) log 3

log(y) /log 3 = (x-1) Remember: Switching log bases: Logb(a) = log(a) / log(b)

log3 (y) = x-1

log3(y) + 1 = x Now switch the y's and x's

y = log3(x) + 1

f'(x) = log3(x) + 1

ElectricPavlov
Mar 4, 2018