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What is the inverse of the function?
y = x^(x-1) solve for 'x
log (y) = (x-1) log 3
log(y) /log 3 = (x-1) Remember: Switching log bases: Logb(a) = log(a) / log(b)
log3 (y) = x-1
log3(y) + 1 = x Now switch the y's and x's
y = log3(x) + 1
f'(x) = log3(x) + 1