+0  
 
0
880
2
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last digit of (2^2^2007)+1

 Jan 3, 2016

Best Answer 

 #2
avatar+128595 
+10

Note:

 

(2^2^2007) + 1  can be expressed as :

 

4^(2007) + 1

 

And the ending digit for all even, positive powers of 4 = 6

 

And the ending digit for all odd, positive powers of 4 = 4

 

So.......

 

(2 ^ 2 ^ 2007)  + 1   = (4^2007) + 1     and since this power of 4 is odd, it ends in a 4....and adding 1 to 4  = 5

 

 

 

cool cool cool

 Jan 3, 2016
 #1
avatar
+5

Here are the last 10 digits of your number, so you can see what the last digit is:8994576385.

 Jan 3, 2016
 #2
avatar+128595 
+10
Best Answer

Note:

 

(2^2^2007) + 1  can be expressed as :

 

4^(2007) + 1

 

And the ending digit for all even, positive powers of 4 = 6

 

And the ending digit for all odd, positive powers of 4 = 4

 

So.......

 

(2 ^ 2 ^ 2007)  + 1   = (4^2007) + 1     and since this power of 4 is odd, it ends in a 4....and adding 1 to 4  = 5

 

 

 

cool cool cool

CPhill Jan 3, 2016

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