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What is the length of a diagonal of a rectangular picture whose side are 12 inches by 17 inches?

 Sep 11, 2014

Best Answer 

 #1
avatar+5478 
+20

Use the Pythagorean Theorem for this problem:

 

$${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

 

In other words: one side of the rectangle squared plus the other side squared equals the diagonal squared.

 

Therefore:

 

$${{\mathtt{12}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{17}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

 

$${\mathtt{144}}{\mathtt{\,\small\textbf+\,}}{\mathtt{289}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

 

$${\mathtt{433}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

Now take the square root of both sides:

 

c = $${\sqrt{{\mathtt{433}}}} = {\mathtt{20.808\: \!652\: \!046\: \!684\: \!811\: \!6}}$$

 Sep 11, 2014
 #1
avatar+5478 
+20
Best Answer

Use the Pythagorean Theorem for this problem:

 

$${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

 

In other words: one side of the rectangle squared plus the other side squared equals the diagonal squared.

 

Therefore:

 

$${{\mathtt{12}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{17}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

 

$${\mathtt{144}}{\mathtt{\,\small\textbf+\,}}{\mathtt{289}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

 

$${\mathtt{433}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

Now take the square root of both sides:

 

c = $${\sqrt{{\mathtt{433}}}} = {\mathtt{20.808\: \!652\: \!046\: \!684\: \!811\: \!6}}$$

kitty<3 Sep 11, 2014

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