What is the length of the side of an equilateral triangle if the height is 7√3
Hello Guest!
\(a^2=(\dfrac{a}{2})^2+(7\sqrt{3})^2\ |\ -(\dfrac{a}{2})^2\\ \dfrac{3a^2}{4}=3\cdot49\\ a=\sqrt{\dfrac{3\cdot 49\cdot 4}{3}}\\ \)
\(a=14\)
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The length of a side is: (7√3) / cos30º = 14