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 what is the maximum point of the equation P(t)=-2t^2+100t+2500

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what is the maximum point of the equation P(t)=-2t^2+100t+2500

 Jun 17, 2015

Best Answer 

 #1
avatar+14538 
+10

P(t) = -2t²+100t+2500


P'(t) = -4t +100


-4t+100 = 0                =>  100=4t            =>           t=25


maximum point ( 25 ; 3750 )

 Jun 17, 2015

1+0 Answers

 #1
avatar+14538 
+10
Best Answer

P(t) = -2t²+100t+2500


P'(t) = -4t +100


-4t+100 = 0                =>  100=4t            =>           t=25


maximum point ( 25 ; 3750 )

radix Jun 17, 2015

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