The arc of an inscribed angle is TWICE the degrees of the angle, so
2(4x-3.5) = 4x+17 solve for x = 6 therefore 4x+17 = 4(6) +17 = 41 degrees
The arc of an inscribed angle is TWICE the degrees of the angle, so
2(4x-3.5) = 4x+17 solve for x = 6 therefore 4x+17 = 4(6) +17 = 41 degrees