What is the number of square units in the area of a triangle whose sides measure 5, 6 and 6 units?

Guest Nov 19, 2020

#1**0 **

Acute isosceles triangle.

Sides: a = 6 b = 6 c = 5

**Area: T = 13.636**

Perimeter: p = 17

Semiperimeter: s = 8.5

Angle ∠ A = 65.376° = 65°22'32″ = 1.141 rad

Angle ∠ B = 65.376° = 65°22'32″ = 1.141 rad

Angle ∠ C = 49.249° = 49°14'55″ = 0.86 rad

The triangle's area using Heron's formula.

Heron's formula gives the area of a triangle when the length of all three sides are known. There is no need to calculate angles or other distances in the triangle first. Heron's formula works equally well in all cases and types of triangles.

T = sqrt{ s(s-a)(s-b)(s-c) },

T =sqrt{ 8.5(8.5-6)(8.5-6)(8.5-5) }

**T =sqrt{ 185.94 } = 13.64 units^2**

Guest Nov 19, 2020

edited by
Guest
Nov 19, 2020