I don't have a lot of experience at this, but I'll give it a go
Arrange the data in order from lowest to highest
0, 1, 1, 2, 2, 2, 2, 2, 3, 3, 4, 4, 5, 5, 6
find the median = 2
find the median of the data set below the median = 2 = first quartile value
find the median of the data set above the median = 4 = third quartile value
Find the inter-quartile range (IQR) = third quartile value - first quartile value = 4 - 2 = 2
To find any possible lower outliers we find all the values less than
first quartile value - 1.5 (IQR) = 2 - (1.5)(2) = 2 - 3 = -1
There are no values less than -1
To find any possible highest outliers, we find all values greater than
third quartile value + 1.5 (IQR) = 4 + (1.5)(2) = 4 + 3 = 7
Tthere are no values greater than 7
So.....no outliers exist