In right △ABC, the right angle is at C, m∠A=30degrees, and AC=7√2 units.
What is the perimeter of △ABC?
options:
B = 60°....AC = 7 √2
A = 30° ....BC = 7 √2 / √3 = (7/3) √6
C = 90° .....AB = (14/3) √6
Perimeter = [ (7/3 + 14/3) √6 + 7 √2 ] = (21/3) √6 + 7 √2 = 7 √6 + 7 √2 units
+296 
