What is the perimeter of the trapezoid shown?
The bottom base can be found as 2 + 2* (2 * cos 60°) = 2 + 4 (1/2) = 2 + 2 = 4
So....the perimeter = 3*2 + 4 = 10
Thank you so much!
![[asy] unitsize(1.5cm);pair a=(0,0); pair b=(1,sqrt(3)); pair c=(3,sqrt(3)); pair d=(4,0);draw(a--b--c--d--a);label(](/api/ssl-img-proxy?src=https%3A%2F%2Flatex.artofproblemsolving.com%2F3%2Fc%2F4%2F3c4675d5f3e80b23b27200e0b538b4fb8d19da26.png)
