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What is the probability that Fatima gets fewer heads than tails if she flips 10 coins?

Guest Jun 21, 2017
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Probability of 0 heads =  C(10, 0) / 2^10

Probabilty of 1 head = C(10,1) / 2^10

Probability of 2 heads  = C(10,2) / 2^10

Probability of 3 heads = C(10,3) / 2^10

Probabilty of 4 heads  = C(10, 4)  / 2^10

 

So....the probabilty of getting fewer heads than tails  =

 

[ C(10,0)  + C(10,1) + C(10,2)  + C(10,3) + C(10,4) ]  / 2^10   = 193/512 ≈ .377  = about 37.7%

 

 

 

cool cool cool

CPhill  Jun 22, 2017

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