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What is the probability that when we roll four fair 6-sided dice, they won't all show the same number?

 Apr 11, 2015

Best Answer 

 #2
avatar+118723 
+5

The number of possibilities if all the dice look different is 6^4

Only 6 of those will have every cie the sames

So   P(all the same number )=     $${\frac{{\mathtt{6}}}{{{\mathtt{6}}}^{{\mathtt{4}}}}} = {\frac{{\mathtt{1}}}{{\mathtt{216}}}} = {\mathtt{0.004\: \!629\: \!629\: \!629\: \!629\: \!6}}$$

 

P (they are not all the same)  =   $${\mathtt{1}}{\mathtt{\,-\,}}\left({\frac{{\mathtt{6}}}{{{\mathtt{6}}}^{{\mathtt{4}}}}}\right) = {\frac{{\mathtt{215}}}{{\mathtt{216}}}} = {\mathtt{0.995\: \!370\: \!370\: \!370\: \!370\: \!4}}$$

 Apr 12, 2015
 #1
avatar+118723 
+5

I am almost positive that I saw this exact question already answered today.

If you want to repost PLEASE do it as requested!

http://web2.0calc.com/questions/instructions-on-reposting_1

 Apr 12, 2015
 #2
avatar+118723 
+5
Best Answer

The number of possibilities if all the dice look different is 6^4

Only 6 of those will have every cie the sames

So   P(all the same number )=     $${\frac{{\mathtt{6}}}{{{\mathtt{6}}}^{{\mathtt{4}}}}} = {\frac{{\mathtt{1}}}{{\mathtt{216}}}} = {\mathtt{0.004\: \!629\: \!629\: \!629\: \!629\: \!6}}$$

 

P (they are not all the same)  =   $${\mathtt{1}}{\mathtt{\,-\,}}\left({\frac{{\mathtt{6}}}{{{\mathtt{6}}}^{{\mathtt{4}}}}}\right) = {\frac{{\mathtt{215}}}{{\mathtt{216}}}} = {\mathtt{0.995\: \!370\: \!370\: \!370\: \!370\: \!4}}$$

Melody Apr 12, 2015

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