What is the process of 4(3x-5)=-2(-x+8)-6?

$$\begin{array}{rlll}
4(3x-5)&=&-2(-x+8)-6x \qquad \mbox{First expand and simplify both sides seperately }\\
12x-20&=&2x-16-6x \qquad \mbox{}\\
12x-20&=&-4x-16 \qquad \mbox{}\\
12x-20+4x&=&-4x-16+4x \qquad \mbox{}\\
16x-20&=&-16 \qquad \mbox{}\\
16x-20+20&=&-16+20 \qquad \mbox{}\\
16x&=&4 \qquad \mbox{}\\
16x/16&=&4/16 \qquad \mbox{}\\
x&=&\frac{1}{4} \qquad \mbox{}\\


\end{array}$$

Sorry sorry it's 4(3x-5)=-2(-x+8)-6x with tha variable at the end.