What is the product of 3√2cis(π/12) and 2√5cis(4π/3)? Enter all values rounded to the nearest hundredth.

[a·cis(A)] · [b·cis(B)  =  a·b·cis(A + B)

 

Multiplying  3sqrt(2) · 2sqrt(5)  =  6sqrt(10)

Adding  pi/12 + 4pi/3  =  17pi/12

 

Answer:  6sqrt(10)cis(17pi/12)