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Given that f(x) = 1/sqrt(x), what is the range of f(x) on the interval (0,inf) ?

 Oct 25, 2020
 #1
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As x starts at some infintesimal value greater than 0 , the funtion is    + inf

   as x goes to infinity the funtion approaches 0

(0, + inf)   would be the range of function values

 Oct 25, 2020

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