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Given that f(x) = 1/3^x, what is the range of f(x) on the interval [0,inf)?

 Nov 14, 2020
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Note that  this function is ever-decreasing from 0  to  infinity

At 0, (1/3)^0  =  1

As x increases without bound, the function approaches  0   [ but never quite gets there ]

 

So....the range  on   [0, inf) =   (0, 1 ]

 

 

cool cool cool

 Nov 14, 2020

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