Given that f(x) = 1/3^x, what is the range of f(x) on the interval [0,inf)?
Note that this function is ever-decreasing from 0 to infinity
At 0, (1/3)^0 = 1
As x increases without bound, the function approaches 0 [ but never quite gets there ]
So....the range on [0, inf) = (0, 1 ]