What is the rectangular form of the parametric equations?
x(t)=t+3,y(t)=2t^2−4 , where t is on the interval [−4,0]
y = ___, where x is on the interval [ __,__ ] .
If x = t + 3 and y = 2t2 - 4
then solve the x-equation for t: x = t + 3 ---> t = x - 3
and substitute this into the other equation: y = 2t2 - 4 ---> y = 2(x - 3)2 - 4
y = 2(x2 - 6x + 9) - 4
y = 2x2 - 12x + 18 - 4
y = 2x2 - 12x + 14
