+0  
 
0
29
1
avatar

What is the rectangular form of the parametric equations?

x(t)=t+3, y(t)=2t^2−4, where t is on the interval [−4,0].

 

y = ____, where x is on the interval [ _,_ ].

 May 18, 2020
 #1
avatar+20883 
0

x  =  t + 3   --->   t  =  x - 3

y  =  2t2 - 4   --->   y  =  2(x - 3)2 - 4   --->   y  =  2(x2 - 6x + 9) - 4   --->   y  =  2x2 - 12x + 14

 

Since the minimum t-value is -4 and x = t + 3, the minimum x value will be -4 + 3  =  -1.

Since the maximum t-value is 0 and x = t + 3, the maximum x-value will be 0 + 3  =  3.

 May 19, 2020

20 Online Users

avatar