What is the rectangular form of the parametric equations?
x(t)=t+3, y(t)=2t^2−4, where t is on the interval [−4,0].
y = ____, where x is on the interval [ _,_ ].
+23254 x = t + 3 ---> t = x - 3
y = 2t2 - 4 ---> y = 2(x - 3)2 - 4 ---> y = 2(x2 - 6x + 9) - 4 ---> y = 2x2 - 12x + 14
Since the minimum t-value is -4 and x = t + 3, the minimum x value will be -4 + 3 = -1.
Since the maximum t-value is 0 and x = t + 3, the maximum x-value will be 0 + 3 = 3.
