+0  
 
0
60
1
avatar+147 

What is the rectangular form of the polar equation?

r−rsinθ=4

 

y=1/8x^2−2

y=8x^2−16

y=8x^2−2

y=1/8x^2−16

 May 3, 2020
 #1
avatar+111396 
+1

r - rsin θ   = 4

 

r - r (y/r)  = 4

 

r - y  =  4

 

r  = 4 + y

 

√[x^2 + y^2]  = 4+ y      square both sides

 

x^2 + y^2  = 16 + 8y + y^2

 

x^2  = 16 + 8y     rearrange as

 

8y  = x^2 - 16       divide both sides by 8

 

y  = (1/8)x^2  - 2

 

 

cool cool cool

 May 3, 2020

9 Online Users