What is the rectangular form of the polar equation?
r−rsinθ=4
y=1/8x^2−2
y=8x^2−16
y=8x^2−2
y=1/8x^2−16
r - rsin θ = 4
r - r (y/r) = 4
r - y = 4
r = 4 + y
√[x^2 + y^2] = 4+ y square both sides
x^2 + y^2 = 16 + 8y + y^2
x^2 = 16 + 8y rearrange as
8y = x^2 - 16 divide both sides by 8
y = (1/8)x^2 - 2