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What is the relative permeability of a ferromagnetic material whose absolute permeability is 750 x 10-6 Wb/At∙m?

 Jul 8, 2014

Best Answer 

 #1
avatar+33665 
+5

Just divide by the permeability of free space  μ0 = 1.2566370614×10−6Wb/A-m

$${\frac{\left({\mathtt{750}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{6}}}\right)}{\left({\mathtt{1.256\: \!637\: \!06}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{6}}}\right)}} = {\mathtt{596.831\: \!037\: \!276\: \!586\: \!447\: \!3}}$$

Relative permeability ≈ 597

 Jul 8, 2014
 #1
avatar+33665 
+5
Best Answer

Just divide by the permeability of free space  μ0 = 1.2566370614×10−6Wb/A-m

$${\frac{\left({\mathtt{750}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{6}}}\right)}{\left({\mathtt{1.256\: \!637\: \!06}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{6}}}\right)}} = {\mathtt{596.831\: \!037\: \!276\: \!586\: \!447\: \!3}}$$

Relative permeability ≈ 597

Alan Jul 8, 2014

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