What is the simplest radical form of the expression?

(x^4y^7)^2/3

Options:

xy^2 3Sqrt x y

x^6y^10 Sqrt y

x^2y^4 3Sqrt x^2y^2

x^3y^5 Sqrtx

My answer-'D' Am I correct?

(x^4y^7)^2/3 =

( [ x^4 y^7] ^2 ) ^1/3 =

( x^8 y^14 ) ^1/3 =

∛ [ x^8 y^14 ] =

To determine the powers that come out and those that stay in, do this

8/3 = 2 + 2/3 2 powers of x come out, 2 stay in

14/3 = 4 + 2/3 4 powers of x come out, 2 stay in

x^2 y ^4 ∛ [x^2 y ^2 ]

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