What is the simplest radical form of the expression?
(x^4y^7)^2/3
Options:
xy^2 3Sqrt x y
x^6y^10 Sqrt y
x^2y^4 3Sqrt x^2y^2
x^3y^5 Sqrtx
My answer-'D' Am I correct?
(x^4y^7)^2/3 =
( [ x^4 y^7] ^2 ) ^1/3 =
( x^8 y^14 ) ^1/3 =
∛ [ x^8 y^14 ] =
To determine the powers that come out and those that stay in, do this
8/3 = 2 + 2/3 2 powers of x come out, 2 stay in
14/3 = 4 + 2/3 4 powers of x come out, 2 stay in
x^2 y ^4 ∛ [x^2 y ^2 ]
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